The density of steel is 490 lb/ft 3 (0.28 lb/in 3). The wall thickness is 0.237 inches and the inside diameter is 4.026 in. The outside diameter of 4" Schedule 40 Steel Pipe is 4.500 inches. = 24.2 kg/m Example - Weight of 4" Schedule 40 Steel Pipe The weight of pipe filled with water per unit length can be calculated with (3) as The weight of the liquid in the pipe per unit length can be calculatet with (2) as: The weight of empty pipe per unit length can be calculatet with (1) as: The outside diameter of 4" Schedule 40 Steel Pipe is 114.3 mm. Ρ l - density of liquid (kg/m 3, lb/in 3) (zero for empty pipe)Įxample - Weight of 4" Schedule 40 Steel Pipe with Water - SI Units (default values in the calculator above) Ρ m - density of piping material (kg/m 3, lb/in 3) The calculator is generic and can be used for both SI and Imperial units as long as the use of units are consistent. This calculator can be used to calculate the weight of a pipe with - or without - liquid. Weight of pipe with liquid can be calculated as
Ρ l = density of liquid (kg/m 3, lb/in 3) W l = weight of liquid in pipe per unit length of pipe (kg, lb)Ī i = cross-sectional inside area of pipe (m 2, in 2) Weight of liquid in pipes per unit length can be calculated as T = wall thickness (m, in) Weight of Liquid in Pipe Ρ m = density of pipe material (kg/m 3, lb/in 3)Ī m = cross-sectional wall area of pipe (m 2, in 2)ĭ i = d o - 2 t = inside diameter (m, in) W p = weight of empty pipe per unit length (kg/m, lb/in) Total steel quantity of column equal to the sum of both main and stirrup steels.Weight of empty pipe per unit length can be calculated as This can be done by multiplying cross section area of steel by its total length by density of steel which 7850 kg/m 3. Convert that length into kilograms or Tons. Estimate total length of stirrup which is equal to stirrup cutting length times number of stirrups.Ĥ.
DENSITY OF STEEL PLUS
Calculate number of stirrup by dividing column height over stirrup spacing plus one.ģ. Compute cutting length of stirrups using the following equationĬutting length=2*((w-cover)+(h-cover))+Ld Equation 10Ģ.Compute total length of longitudinal bars which equal to the column height plus laps for footing multiply number of longitudinal bars.Then, compute quantity of steel in the column using the following steps: Therefore, for footings with the double reinforcing net, the same procedure need to be used again to compute steel quantity for another reinforcing net.Īchieve column size and reinforcement detailing from design drawings. The above calculation procedure is for single reinforcing net. This can be done by multiplying cross section area of steel by its total length by density of steel which 7850 kg/m 3 Convert that length into kilograms or Tons.If the same size of bars is used in both directions then you can sum up both quantity of the bars After that, compute the total length of bars which is equal to the number of required bars multiply by the length of one bar.Where L or W is length or width of footing Length of bar = L or W–concrete cover for both sides + 2*bend length Equation 9 calculate the required number of bars for both directions.After that, the following steps will be taken to compute steel quantity. This can be achieved from design drawings. Size of footing and its reinforcement details (bar size and spacing) shall be known. ( /162) is the weight of a steel which is derived from steel volume times its density which is 7850 kg/m 3. of bars*cutting length*weight of the bar ( /162) Equation 7 The same equation used for both main and shrinkage and temperature reinforcement, but corresponding cutting length, number of bars, and bar diameter is used. Convert that length into kilograms or tons because steel bars are ordered by weight.
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